A refrigerator is to maintain eatables at 9° C . If room temperature is 36° C, then the coefficient of performance is

Question

A refrigerator is to maintain eatables at 9° C . If room temperature is 36° C, then the coefficient of performance is (A) 8.6 (B) 10.4 (C) 11.2 (D) 12.5

Tardigrade Admin · Accepted Answer

α=(O2/Q1-Q2) Assuming the refrigerator to be a Carnot refrigerator, where (Q1/T1)=(Q2/T2) α=(T2/T1-T2) =((9+273) K /(36+273) K -(9+273) K )=(282 K /27 K )=10.4.

Q. A refrigerator is to maintain eatables at $9^{\circ} C .$ If room temperature is $3 6^{\circ} C$ , then the coefficient of performance is

8.6

10.4

11.2

12.5

$α = \frac{O _{2}}{Q _{1} - Q _{2}}$
Assuming the refrigerator to be a Carnot refrigerator, where
$\frac{Q _{1}}{T _{1}} = \frac{Q _{2}}{T _{2}}$
$α = \frac{T _{2}}{T _{1} - T _{2}}$
$= \frac{( 9 + 273 ) K}{( 36 + 273 ) K - ( 9 + 273 ) K} = \frac{282 K}{27 K} = 10.4$ .

Q. A refrigerator is to maintain eatables at 9∘C. If room temperature is 36∘C, then the coefficient of performance is

8.6

10.4

11.2

12.5

α=Q1​−Q2​O2​​ Assuming the refrigerator to be a Carnot refrigerator, where T1​Q1​​=T2​Q2​​ α=T1​−T2​T2​​ =(36+273)K−(9+273)K(9+273)K​=27K282K​=10.4.

Q. A refrigerator is to maintain eatables at $9^{\circ} C .$ If room temperature is $3 6^{\circ} C$ , then the coefficient of performance is

$α = \frac{O _{2}}{Q _{1} - Q _{2}}$
Assuming the refrigerator to be a Carnot refrigerator, where
$\frac{Q _{1}}{T _{1}} = \frac{Q _{2}}{T _{2}}$
$α = \frac{T _{2}}{T _{1} - T _{2}}$
$= \frac{( 9 + 273 ) K}{( 36 + 273 ) K - ( 9 + 273 ) K} = \frac{282 K}{27 K} = 10.4$ .