A reaction is first order with respect to a gaseous reactant A and second order with respect to a gaseous reactant B. If volume of the mixture is doubled, the rate of reaction becomes

Question

A reaction is first order with respect to a gaseous reactant A and second order with respect to a gaseous reactant B. If volume of the mixture is doubled, the rate of reaction becomes (A) (1/8)th times (B) 8 × (C) (1/4)th times (D) 4 ×

Tardigrade Admin · Accepted Answer

Rate = k[A][B]2 ; volume is doubled so, concentration is halved.

Q. A reaction is first order with respect to a gaseous reactant A and second order with respect to a gaseous reactant B. If volume of the mixture is doubled, the rate of reaction becomes

$\frac{1}{8}$ th times

$8 \times$

$\frac{1}{4}$ th times

$4 \times$

Rate = $k [A] [B]^{2}$ ; volume is doubled so, concentration is halved.