A reaction in which reactants (R) are converted into products (P) follows second order kinetics. If concentration of R is increased by four times, what will be the increase in the rate of formation of P?

Question

A reaction in which reactants (R) are converted into products (P) follows second order kinetics. If concentration of R is increased by four times, what will be the increase in the rate of formation of P? (A) 9 times (B) 4 times (C) 16 times (D) 8 times

Tardigrade Admin · Accepted Answer

R → P For a second order reaction, rate = k[R]2 If conc, of R is increased by four times, rate = k[4R]2 Hence, the rate of formation of P increases by 16 times.

Q. A reaction in which reactants $(R)$ are converted into products $(P)$ follows second order kinetics. If concentration of $R$ is increased by four times, what will be the increase in the rate of formation of $P$ ?

$9$ times

$4$ times

$16$ times

$8$ times

$R \to P$
For a second order reaction, rate $= k [R]^{2}$
If conc, of $R$ is increased by four times, rate $= k [4 R]^{2}$
Hence, the rate of formation of $P$ increases by $16$ times.

Q. A reaction in which reactants (R) are converted into products (P) follows second order kinetics. If concentration of R is increased by four times, what will be the increase in the rate of formation of P?

9 times

4 times

16 times

8 times