A ray of monochromatic light is incident on one refracting face of a prism of angle 75° . It passes through the prism and is incident on the other face at the critical angle. If the refractive index of the material of prism is √2, , the angle of incidence on the first face of the prism is :

Question

A ray of monochromatic light is incident on one refracting face of a prism of angle 75° . It passes through the prism and is incident on the other face at the critical angle. If the refractive index of the material of prism is √2, , the angle of incidence on the first face of the prism is : (A)  0°  (B)  60°  (C)  45°  (D)  30°

Tardigrade Admin · Accepted Answer

For critical angle Sin C=(1/μ ) sin C=(1/√2)= sin 45o C=45o it means angle of emergence e=45o For prism angle of incident I = e=45o

$0^{\circ}$

$60^{\circ}$

$45^{\circ}$

$30^{\circ}$

For critical angle $S in C = \frac{1}{μ}$ $sin C = \frac{1}{2} = sin 45^{o}$ $C = 45^{o}$ it means angle of emergence $e = 45^{o}$ For prism angle of incident I = $e = 45^{o}$

Q. A ray of monochromatic light is incident on one refracting face of a prism of angle 75∘ . It passes through the prism and is incident on the other face at the critical angle. If the refractive index of the material of prism is 2,​ , the angle of incidence on the first face of the prism is :

0∘

60∘

45∘

30∘

For critical angle SinC=μ1​ sinC=2​1​=sin45o C=45o it means angle of emergence e=45o For prism angle of incident I = e=45o

$0^{\circ}$

$60^{\circ}$

$45^{\circ}$

$30^{\circ}$

For critical angle $S in C = \frac{1}{μ}$ $sin C = \frac{1}{2} = sin 45^{o}$ $C = 45^{o}$ it means angle of emergence $e = 45^{o}$ For prism angle of incident I = $e = 45^{o}$