A ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle φ. If μ represents the refractive index of glass with respect to air, then the angle between reflected and refracted rays is

Question

A ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle φ. If μ represents the refractive index of glass with respect to air, then the angle between reflected and refracted rays is (A) 90°+φ (B)  sin -1(μ cos φ) (C) 90° (D) 90°- sin -1( sin φ / μ)

Tardigrade Admin · Accepted Answer

At polarizing angle, the reflected and refracted rays are mutually perpendicular to each other.

Q. A ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle $ϕ$ . If $μ$ represents the refractive index of glass with respect to air, then the angle between reflected and refracted rays is

$9 0^{\circ} + ϕ$

$sin^{- 1} (μ cos ϕ)$

$9 0^{\circ}$

$9 0^{\circ} - sin^{- 1} (sin ϕ / μ)$

At polarizing angle, the reflected and refracted rays are mutually perpendicular to each other.

Q. A ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle ϕ. If μ represents the refractive index of glass with respect to air, then the angle between reflected and refracted rays is

90∘+ϕ

sin−1(μcosϕ)

90∘

90∘−sin−1(sinϕ/μ)

At polarizing angle, the reflected and refracted rays are mutually perpendicular to each other.

Q. A ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle $ϕ$ . If $μ$ represents the refractive index of glass with respect to air, then the angle between reflected and refracted rays is

$9 0^{\circ} + ϕ$

$sin^{- 1} (μ cos ϕ)$

$9 0^{\circ}$

$9 0^{\circ} - sin^{- 1} (sin ϕ / μ)$