Question

A ray of light is incident at an angle of $45^{\circ }$ on one face of a rectangular glass slab of thickness $10cm$ and refractive index $3/2.$ Calculate the lateral shift produced:

• A. $0.33m$
• B. $0.45cm$
• C. $0.033m$
• D. $0.045m$

Answer 1

Answer: (C)

Here $i=45^{\circ },t=10cm=0.1m$,
$\mu =1.5$ lateral shift $=?$
As, $\mu =\frac{\sin i_1}{\sin r_1}$
$\therefore \sin r_1=\frac{\sin i_1}{\mu }=\frac{\sin 45^0}{1.5}$
$\sin r_1=\frac{0.707}{1.5}$
$r_1=28.14^0$
lateral shift $=\frac{t\sin \left(i_1-r_1\right)}{\cos r_1}$
Lateral shift $=0.033m$