Question

A ray of light is incident at an angle of $45^{\circ}$ on one face of a rectangular glass slab of thickness $10 cm$ and refractive index $3 / 2 .$ Calculate the lateral shift produced:

• A. $0.33 m$
• B. $0.45 cm$
• C. $0.033 m$
• D. $0.045 m$

Answer 1

Answer: (C)

Here $i=45^{\circ}, t=10 cm =0.1 m $,
$ \mu=1.5$ lateral shift $=?$
As, $\mu=\frac{\sin i_{1}}{\sin r_{1}}$
$\therefore \sin r_{1}=\frac{\sin i_{1}}{\mu}=\frac{\sin 45^{0}}{1.5}$
$\sin r_{1}=\frac{0.707}{1.5}$
$r_{1}=28.14^{0}$
lateral shift $=\frac{t \sin \left(i_{1}-r_{1}\right)}{\cos r_{1}}$
Lateral shift $=0.033 m$