A ray of light enters a rectangular glass slab of refractive index √3 at an angle of incidence 60°.It travels a distance 5 cm inside and emerges out of slab. The perpendicular distance between the incidence and the emergent ray is

Question

A ray of light enters a rectangular glass slab of refractive index √3 at an angle of incidence 60°.It travels a distance 5 cm inside and emerges out of slab. The perpendicular distance between the incidence and the emergent ray is (A) 5 √3 cm (B) 5 / √3 cm (C) 5 / 2 cm (D) 5 cm

Tardigrade Admin · Accepted Answer

sin 60°=n sin r ⇒ r=30° x=d sin (i-r)=5 × sin 30°=5 / 2 cm

Q. A ray of light enters a rectangular glass slab of refractive index $3$ at an angle of incidence $6 0^{\circ}$ .It travels a distance $5 c m$ inside and emerges out of slab. The perpendicular distance between the incidence and the emergent ray is

$53 c m$

$5/ 3 c m$

$5/2 c m$

$5 c m$

$sin 6 0^{\circ} = n sin r$
$\Rightarrow r = 3 0^{\circ}$
$x = d sin (i - r) = 5 \times sin 3 0^{\circ} = 5/2 c m$

Q. A ray of light enters a rectangular glass slab of refractive index 3​ at an angle of incidence 60∘.It travels a distance 5cm inside and emerges out of slab. The perpendicular distance between the incidence and the emergent ray is

53​cm

5/3​cm

5/2cm

5cm