A radioactive nucleus Z A X undergoes spontaneous decay in the sequence Z A X arrow z-1 B arrow Z -3 C arrow Z -2 D, where Z is the atomic number of element X. The possible decay particles in the sequence are :

Question

A radioactive nucleus Z A X undergoes spontaneous decay in the sequence Z A X arrow z-1 B arrow Z -3 C arrow Z -2 D, where Z is the atomic number of element X. The possible decay particles in the sequence are : (A) α, β-, β+ (B) α, β+, β- (C) β+, α, β- (D) β-, α, β+

Tardigrade Admin · Accepted Answer

z X A arrow z-1 B (β+.decay ) z-1 B arrowz-3 C (α- decay ) z-3 C arrow z-2 D (β-.decay )

Q. A radioactive nucleus $_{Z}^{A} X$ undergoes spontaneous decay in the sequence
$_{Z}^{A} X \to_{z - 1} B \to_{Z - 3} C \to_{Z - 2} D$ , where $Z$ is the atomic number of element $X$ . The possible decay particles in the sequence are :

$α, β^{-}, β^{+}$

$α, β^{+}, β^{-}$

$β^{+}, α, β^{-}$

$β^{-}, α, β^{+}$

$_{z} X^{A} \to_{z - 1} B (β^{+}$ decay $)$
$_{z - 1} B \to_{z - 3} C (α -$ decay $)$
$_{z - 3} C \to_{z - 2} D (β^{-}$ decay $)$

Q. A radioactive nucleus ZA​X undergoes spontaneous decay in the sequence ZA​X→z−1​B→Z−3​C→Z−2​D, where Z is the atomic number of element X. The possible decay particles in the sequence are :

α,β−,β+

α,β+,β−

β+,α,β−

β−,α,β+