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Question
Physics
A radio receiver antenna that is 2 m long is oriented along the direction of the electromagnetic wave and receives a signal of intensity 5 × 10-16 W / m 2. The maximum instantaneous potential difference across the two ends of the antenna is
Q. A radio receiver antenna that is
2
m
long is oriented along the direction of the electromagnetic wave and receives a signal of intensity
5
×
1
0
−
16
W
/
m
2
. The maximum instantaneous potential difference across the two ends of the antenna is
2031
208
Electromagnetic Waves
Report Error
A
1.23
μ
V
25%
B
1.23
mV
34%
C
1.23
V
26%
D
12.3
mV
15%
Solution:
I
=
2
1
ε
0
c
E
0
2
⇒
E
0
=
ε
0
c
2
I
=
8.85
×
1
0
−
12
×
3
×
1
0
8
2
×
5
×
1
0
−
16
=
0.61
×
1
0
−
6
m
V
Also
E
0
=
d
V
0
⇒
V
0
=
E
0
d
=
0.61
×
1
0
−
6
×
2
=
1.23
μ
V