A proton with energy of 2 MeV enters a uniform magnetic field of2.5 T normally. The magnetic force on the proton is (Take mass of proton to be 1.6 × 10-27 kg )

Question

A proton with energy of 2 MeV enters a uniform magnetic field of2.5 T normally. The magnetic force on the proton is (Take mass of proton to be 1.6 × 10-27 kg ) (A) 3 × 10-12N (B) 8 × 10-10N (C) 8 × 10-12N (D) 2 × 10-10N

Tardigrade Admin · Accepted Answer

Energy of proton = 2 MeV =2 × 1.6×10-19×106 J =3.2 × 10-13J Magnetic field (B)=2.5 T Mass of proton (m) =1.6 × 10-27kg Energy of proton E= (1/2)mv2 ∴ v= √ (2E/m) ...(i) Magnetic force on proton F=Bqv sin 90° =Bqv Substituting the value of v from Eq. (i) F=Bq √ (2E/m) =2.5 × 1.6×10-19 √ (2×3.2×10-13/1.6 × 10-27) =8 × 10-12N

Q. A proton with energy of 2 MeV enters a uniform
magnetic field of2.5 T normally. The magnetic force on
the proton is
(Take mass of proton to be $1.6 \times 1 0^{- 27} k g)$

$3 \times 1 0^{- 12} N$

$8 \times 1 0^{- 10} N$

$8 \times 1 0^{- 12} N$

$2 \times 1 0^{- 10} N$

$3 \times 1 0^{- 10} N$

Q. A proton with energy of 2 MeV enters a uniform magnetic field of2.5 T normally. The magnetic force on the proton is (Take mass of proton to be 1.6×10−27kg)

3×10−12N

8×10−10N

8×10−12N

2×10−10N