A proton of mass ‘m’ moving with a speed v (

Question

A proton of mass ‘m’ moving with a speed v (<< c, velocity of light in vacuum) completes a circular orbit in time ‘T’ in a uniform magnetic field. If the speed of the proton is increased to 2 v, what will be time needed to complete the circular orbit ? (A) √2 T (B) T (C) (T/√2) (D) (T/2)

Tardigrade Admin · Accepted Answer

∵ When a charged particle moves at a circular path in uniform magnetic field, it time period is independent from its speed. ∴ Time period of proton will not change with change in its speed

Q. A proton of mass ‘ $m$ ’ moving with a speed $v (<< c$ , velocity of light in vacuum) completes a circular orbit in time ‘ $T$ ’ in a uniform magnetic field. If the speed of the proton is increased to $2 v$ , what will be time needed to complete the circular orbit ?

$2$ T

T

$\frac{T}{2}$

$\frac{T}{2}$

$∵$ When a charged particle moves at a circular path in uniform magnetic field, it time period is independent from its speed.
$∴$ Time period of proton will not change with change in its speed

Q. A proton of mass ‘m’ moving with a speed v(<<c, velocity of light in vacuum) completes a circular orbit in time ‘T’ in a uniform magnetic field. If the speed of the proton is increased to 2v, what will be time needed to complete the circular orbit ?

2​ T

T

2​T​

2T​

∵ When a charged particle moves at a circular path in uniform magnetic field, it time period is independent from its speed. ∴ Time period of proton will not change with change in its speed

Q. A proton of mass ‘ $m$ ’ moving with a speed $v (<< c$ , velocity of light in vacuum) completes a circular orbit in time ‘ $T$ ’ in a uniform magnetic field. If the speed of the proton is increased to $2 v$ , what will be time needed to complete the circular orbit ?

$2$ T

$\frac{T}{2}$

$\frac{T}{2}$

$∵$ When a charged particle moves at a circular path in uniform magnetic field, it time period is independent from its speed.
$∴$ Time period of proton will not change with change in its speed