A proton moving with a velocity of 1.25× 105 m s- 1 collides with a stationary helium atom. The velocity of the proton after the collision is

Question

A proton moving with a velocity of 1.25× 105 m s- 1 collides with a stationary helium atom. The velocity of the proton after the collision is (A) 0.75× 105 m s- 1 (B) 7.5× 105 m s- 1 (C) -0.75× 105 m s- 1 (D) 0 m s- 1

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-2qo1f4xwjbwg.png" /> From momentum conservation textmpu1= textmpv1+ textmHev2 ⇒ u1=v1+4v2 ...(i) For elastic collision e=1 e=(v2 - v1/u1) ⇒ u1=v2-v1 ...(ii) From equation (i) and equation (ii), we get v2=(2/5)u1 text and v1=-(3/5)u1 ∴ v1=-(3/5)× text1.25× 105ms- 1=- text0.75× 105ms- 1

Q. A proton moving with a velocity of $1.25 \times 1 0^{5} m s^{- 1}$ collides with a stationary helium atom. The velocity of the proton after the collision is

$0.75 \times 1 0^{5} m s^{- 1}$

$7.5 \times 1 0^{5} m s^{- 1}$

$- 0.75 \times 1 0^{5} m s^{- 1}$

$0 m s^{- 1}$

Q. A proton moving with a velocity of 1.25×105ms−1 collides with a stationary helium atom. The velocity of the proton after the collision is

0.75×105ms−1

7.5×105ms−1

−0.75×105ms−1

0ms−1

Q. A proton moving with a velocity of $1.25 \times 1 0^{5} m s^{- 1}$ collides with a stationary helium atom. The velocity of the proton after the collision is

$0.75 \times 1 0^{5} m s^{- 1}$

$7.5 \times 1 0^{5} m s^{- 1}$

$- 0.75 \times 1 0^{5} m s^{- 1}$

$0 m s^{- 1}$