Question

A proton is projected with a uniform velocity $v$ along the axis of a current-carrying solenoid, then

• A. The proton will be accelerated along the axis
• B. The proton path will be circular about the axis
• C. The proton move along helical path
• D. The proton will continue to move with velocity $v$ along the axis

Answer 1

Answer: (D)

The force on a charged particle in magnitude field
$F=q\left(v\times B\right)$
The proton is moving along the axis of solenoid. Magnetic field inside the solenoid is parallel to the axis of solenoid.
$\therefore \overrightarrow{v}\parallel \overrightarrow{B}$
$F=qvBsin\theta$
$\theta =0$
$F=0$
$\therefore$ The proton will continue to move with velocity along the axis.