A proton and an electron are released infinite distance apart and are attracted towards each other. Which of the following statement about their kinetic energy is true ?

Question

A proton and an electron are released infinite distance apart and are attracted towards each other. Which of the following statement about their kinetic energy is true ? (A) Kinetic energy of electron is more than that of proton (B) Kinetic energy of electron is less than that of proton (C) Kinetic energy of electron = kinetic energy of proton (D) None of the above is true as it depends on the distance between the particles

Tardigrade Admin · Accepted Answer

Both particles move towards each other with equal and opposite forces. Kinetic energy acquired, K = (1/2) m v2 = (1/2) m (at)2 = (1/2) m ( (F/m)t)2 or K propto (1/m)

Q. A proton and an electron are released infinite distance apart and are attracted towards each other. Which of the following statement about their kinetic energy is true ?

Kinetic energy of electron is more than that of proton

Kinetic energy of electron is less than that of proton

Kinetic energy of electron = kinetic energy of proton

None of the above is true as it depends on the distance between the particles

Both particles move towards each other with equal and opposite forces.
Kinetic energy acquired, $K = \frac{1}{2} m v^{2} = \frac{1}{2} m (a t)^{2} = \frac{1}{2} m (\frac{F}{m} t)^{2}$
or $K \propto \frac{1}{m}$

Q. A proton and an electron are released infinite distance apart and are attracted towards each other. Which of the following statement about their kinetic energy is true ?

Kinetic energy of electron is more than that of proton

Kinetic energy of electron is less than that of proton

Kinetic energy of electron = kinetic energy of proton

None of the above is true as it depends on the distance between the particles

Both particles move towards each other with equal and opposite forces. Kinetic energy acquired, K=21​mv2=21​m(at)2=21​m(mF​t)2 or K∝m1​

Both particles move towards each other with equal and opposite forces.
Kinetic energy acquired, $K = \frac{1}{2} m v^{2} = \frac{1}{2} m (a t)^{2} = \frac{1}{2} m (\frac{F}{m} t)^{2}$
or $K \propto \frac{1}{m}$