A proton, an electron, and a Helium nucleus, have the same energy. They are in circular orbits in a plane due to magnetic field perpendicualr to the plane. Let rp, re and rHe be their respective radii, then,

Question

A proton, an electron, and a Helium nucleus, have the same energy. They are in circular orbits in a plane due to magnetic field perpendicualr to the plane. Let rp, re and rHe be their respective radii, then, (A) re > rp > rHe (B) re < rp < rHe (C) re < rp = rHe (D) re > rp = rHe

Tardigrade Admin · Accepted Answer

r = (mv/qB) = (√2mK/qB) rHe = rp > re

Q. A proton, an electron, and a Helium nucleus, have the same energy. They are in circular orbits in a plane due to magnetic field perpendicualr to the plane. Let $r_{p}, r_{e}$ and $r_{He}$ be their respective radii, then,

$r_{e} > r_{p} > r_{He}$

$r_{e} < r_{p} < r_{He}$

$r_{e} < r_{p} = r_{He}$

$r_{e} > r_{p} = r_{He}$

$r = \frac{m v}{qB} = \frac{2 m K}{qB}$
$r_{He} = r_{p} > r_{e}$

Q. A proton, an electron, and a Helium nucleus, have the same energy. They are in circular orbits in a plane due to magnetic field perpendicualr to the plane. Let rp​,re​ and rHe​ be their respective radii, then,

re​>rp​>rHe​

re​<rp​<rHe​

re​<rp​=rHe​

re​>rp​=rHe​