A projectile is thrown obliquely into the air from origin of a reference frame with y-axis vertically upward and x- axis perpendicular to y then equation of motion has the form

Question

A projectile is thrown obliquely into the air from origin of a reference frame with y-axis vertically upward and x- axis perpendicular to y then equation of motion has the form (A)  y=ax+bx2  (B)  y=ax2+bx3  (C)  y=a+bx  (D)  y=(a+b)x

Tardigrade Admin · Accepted Answer

: For a projectile motion, the trajectory is a parabola. It is a first degree equation in y and second degree equation in

x

for a parabola. Hence the form of equation is

y = a x + b x^{2}

.
Here a and b are constants.

Q. A projectile is thrown obliquely into the air from origin of a reference frame with y-axis vertically upward and $x -$ axis perpendicular to y then equation of motion has the form

$y = a x + b x^{2}$

$y = a x^{2} + b x^{3}$

$y = a + b x$

$y = (a + b) x$

: For a projectile motion, the trajectory is a parabola. It is a first degree equation in y and second degree equation in $x$ for a parabola. Hence the form of equation is $y = a x + b x^{2}$ .
Here a and b are constants.

Q. A projectile is thrown obliquely into the air from origin of a reference frame with y-axis vertically upward and x− axis perpendicular to y then equation of motion has the form

y=ax+bx2

y=ax2+bx3

y=a+bx

y=(a+b)x