A projectile is thrown from a point in a horizontal plane such that its horizontal and vertical velocity component are 9.8 m / s and 19.6 m / s respectively. Find its horizontal range (in m)

Question

A projectile is thrown from a point in a horizontal plane such that its horizontal and vertical velocity component are 9.8 m / s and 19.6 m / s respectively. Find its horizontal range (in m) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

∵ Time of flight =(2 × v y / g ) =(2 × 19.6/9.8)=4 sec Now range = T × v x =4 × 9.8=39.2 m

Q. A projectile is thrown from a point in a horizontal plane such that its horizontal and vertical velocity component are $9.8 m / s$ and $19.6 m / s$ respectively. Find its horizontal range (in $m$ )

$∵$ Time of flight $= \frac{2 \times v _{y}}{g}$
$= \frac{2 \times 19.6}{9.8} = 4 sec$
Now range $= T \times v_{x}$
$= 4 \times 9.8 = 39.2 m$

Q. A projectile is thrown from a point in a horizontal plane such that its horizontal and vertical velocity component are 9.8m/s and 19.6m/s respectively. Find its horizontal range (in m)

∵ Time of flight =g2×vy​​ =9.82×19.6​=4sec Now range =T×vx​ =4×9.8=39.2m

Q. A projectile is thrown from a point in a horizontal plane such that its horizontal and vertical velocity component are $9.8 m / s$ and $19.6 m / s$ respectively. Find its horizontal range (in $m$ )

$∵$ Time of flight $= \frac{2 \times v _{y}}{g}$
$= \frac{2 \times 19.6}{9.8} = 4 sec$
Now range $= T \times v_{x}$
$= 4 \times 9.8 = 39.2 m$