A projectile is fired with a velocity u making an angle θ with the horizontal. What is the magnitude of change in velocity when it is at the highest point -

Question

A projectile is fired with a velocity u making an angle θ with the horizontal. What is the magnitude of change in velocity when it is at the highest point - (A) u cos θ (B) u (C) u sin θ (D) u cos θ - u

Tardigrade Admin · Accepted Answer

The thing to note is when the projectile reaches it's highest point, it has lost all of its vertical velocity.
The vertical velocity of this projectile is

u sin θ

and since the projectile loses this velocity, it would have a difference of

u sin θ

.

Q. A projectile is fired with a velocity $u$ making an angle $θ$ with the horizontal. What is the magnitude of change in velocity when it is at the highest point -

$u cos θ$

$u$

$u sin θ$

$u cos θ - u$

The thing to note is when the projectile reaches it's highest point, it has lost all of its vertical velocity.
The vertical velocity of this projectile is $u sin θ$ and since the projectile loses this velocity, it would have a difference of $u sin θ$ .

Q. A projectile is fired with a velocity u making an angle θ with the horizontal. What is the magnitude of change in velocity when it is at the highest point -

ucosθ

u

usinθ

ucosθ−u

The thing to note is when the projectile reaches it's highest point, it has lost all of its vertical velocity. The vertical velocity of this projectile is usinθ and since the projectile loses this velocity, it would have a difference of usinθ.

Q. A projectile is fired with a velocity $u$ making an angle $θ$ with the horizontal. What is the magnitude of change in velocity when it is at the highest point -

$u cos θ$

$u$

$u sin θ$

$u cos θ - u$

The thing to note is when the projectile reaches it's highest point, it has lost all of its vertical velocity.
The vertical velocity of this projectile is $u sin θ$ and since the projectile loses this velocity, it would have a difference of $u sin θ$ .