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Tardigrade
Question
Chemistry
A process has Δ H = 200 J mol-1 and Δ S = 40 JK-1 mol-1. Out of the values given below, choose the minimum temperature above which the process will be spontaneous :
Q. A process has
Δ
H
=
200
J
m
o
l
−
1
and
Δ
S
=
40
J
K
−
1
m
o
l
−
1
. Out of the values given below, choose the minimum temperature above which the process will be spontaneous :
3341
232
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JEE Main 2019
Thermodynamics
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A
5
K
50%
B
4
K
5%
C
20
K
27%
D
12
K
18%
Solution:
Δ
G
=
Δ
H
−
T
Δ
S
T
=
Δ
S
Δ
H
=
40
200
=
5
K