1. Tardigrade
  2. Question
  3. Chemistry
  4. A process has Δ H = 200 J mol-1 and Δ S = 40 JK-1 mol-1. Out of the values given below, choose the minimum temperature above which the process will be spontaneous :

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Q. A process has $\Delta H = 200 \; J mol^{-1}$ and $\Delta S = 40 \; JK^{-1} mol^{-1}$. Out of the values given below, choose the minimum temperature above which the process will be spontaneous :

JEE MainJEE Main 2019Thermodynamics

Solution:

$\Delta G = \Delta H -T\Delta S$
$T = \frac{\Delta H}{\Delta S} = \frac{200}{40} = 5K $