Question

A pressure of $10^6$ dyne $c{m}^{-2}$ is equivalent to

• A. $10^{5}N{m}^{-2}$
• B. $10^{4}N{m}^{-2}$
• C. $10^{6}N{m}^{-2}$
• D. $10^{7}N{m}^{-2}$

Answer 1

Answer: (A)

1 Newton $=10^5$ dyne and $1m=100cm$
$10^6$ dyne $c{m}^{-2}=10^6\times 10^{-5}N\times {\left(10^{-2}m\right)}^2=10^{5}N{m}^{-2}$