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Q. A pressure of $10^{6}$ dyne $cm ^{-2}$ is equivalent to

Physical World, Units and Measurements

Solution:

1 Newton $=10^{5}$ dyne and $1\, m =100\, cm$
$10^{6}$ dyne $cm ^{-2}=10^{6} \times 10^{-5} N \times\left(10^{-2} m \right)^{2}=10^{5} Nm ^{-2}$