A power transmission line feeds input power at 2400 V to a step-down transformer which delivers power at 240 V with its primary windings having 5000 turns. If the current in the primary coil of the transformer is 5 A and its efficiency is 80 %, then what is the output current (in A )?

Question

A power transmission line feeds input power at 2400 V to a step-down transformer which delivers power at 240 V with its primary windings having 5000 turns. If the current in the primary coil of the transformer is 5 A and its efficiency is 80 %, then what is the output current (in A )? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

ϵ p=2400V,Np=5000 ϵ s=240V,Ip=5A η=80 %=0.8 η=(Pout/Pin)=(ϵ s Is/ϵ p Ip) ⇒ Is=(η ϵ p Ip/ϵ s)=(0 . 8 × 2400 × 5/240)=40A

Q. A power transmission line feeds input power at $2400 V$ to a step-down transformer which delivers power at $240 V$ with its primary windings having $5000$ turns. If the current in the primary coil of the transformer is $5 A$ and its efficiency is $80%,$ then what is the output current (in $A$ )?

$ϵ_{p} = 2400 V, N_{p} = 5000$
$ϵ_{s} = 240 V, I_{p} = 5 A$
$η = 80% = 0.8$
$η = \frac{P _{o u t}}{P _{in}} = \frac{ϵ _{s} I _{s}}{ϵ _{p} I _{p}}$
$\Rightarrow I_{s} = \frac{η ϵ _{p} I _{p}}{ϵ _{s}} = \frac{0.8 \times 2400 \times 5}{240} = 40 A$

Q. A power transmission line feeds input power at 2400V to a step-down transformer which delivers power at 240V with its primary windings having 5000 turns. If the current in the primary coil of the transformer is 5A and its efficiency is 80%, then what is the output current (in A )?

ϵp​=2400V,Np​=5000 ϵs​=240V,Ip​=5A η=80%=0.8 η=Pin​Pout​​=ϵp​Ip​ϵs​Is​​ ⇒Is​=ϵs​ηϵp​Ip​​=2400.8×2400×5​=40A

Q. A power transmission line feeds input power at $2400 V$ to a step-down transformer which delivers power at $240 V$ with its primary windings having $5000$ turns. If the current in the primary coil of the transformer is $5 A$ and its efficiency is $80%,$ then what is the output current (in $A$ )?

$ϵ_{p} = 2400 V, N_{p} = 5000$
$ϵ_{s} = 240 V, I_{p} = 5 A$
$η = 80% = 0.8$
$η = \frac{P _{o u t}}{P _{in}} = \frac{ϵ _{s} I _{s}}{ϵ _{p} I _{p}}$
$\Rightarrow I_{s} = \frac{η ϵ _{p} I _{p}}{ϵ _{s}} = \frac{0.8 \times 2400 \times 5}{240} = 40 A$