A potentiometer consists of a wire of length 4 m and resistance 10 Ω It is connected to a cell of e.m.f. 2 V. The potential difference per unit length of the wire will be

Question

A potentiometer consists of a wire of length 4 m and resistance 10 Ω It is connected to a cell of e.m.f. 2 V. The potential difference per unit length of the wire will be (A) 5 V/m (B) 2 V/m (C) 0.5 V/m (D) 10 V/m

Tardigrade Admin · Accepted Answer

i=(2/10)=0.2 A,(R/l)=10/4 Potential difference per unit length =0.2 × (10/4) = 0.5 V/m

Q. A potentiometer consists of a wire of length $4 m$ and resistance $10 Ω$ It is connected to a cell of e.m.f. $2 V$ . The potential difference per unit length of the wire will be

5 V/m

2 V/m

0.5 V/m

10 V/m

$i = \frac{2}{10} = 0.2 A, \frac{R}{l} = 10/4$
Potential difference per unit length
$= 0.2 \times (10/4) = 0.5 V / m$

Q. A potentiometer consists of a wire of length 4m and resistance 10Ω It is connected to a cell of e.m.f. 2V. The potential difference per unit length of the wire will be