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  4. A potentiometer consists of a wire of length 4 m and resistance 10 Ω It is connected to a cell of e.m.f. 2 V. The potential difference per unit length of the wire will be

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Q. A potentiometer consists of a wire of length $4\, m$ and resistance $10\, \Omega$ It is connected to a cell of e.m.f. $2 \,V$. The potential difference per unit length of the wire will be

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Solution:

$i=\frac{2}{10}=0.2 \, A,\frac{R}{l}=10/4$
Potential difference per unit length
$\, \, =0.2 \times (10/4) = 0.5\, V/m $