A potential difference of 5 V is applied across a conductor of length 10 cm. If drift velocity of electrons is 2.5 × 10-4 m / s, then electron mobility will be

Question

A potential difference of 5 V is applied across a conductor of length 10 cm. If drift velocity of electrons is 2.5 × 10-4 m / s, then electron mobility will be (A) 5 × 10-4 m 2 V -1 s -1 (B) 5 × 10-6 m 2 V -1 s -1 (C) 5 × 10-2 m 2 V -1 s -1 (D) Zero

Tardigrade Admin · Accepted Answer

μ=(VD/E) μ=(2.5 × 10-4 × 0.1/5) μ=5 × 10-6 m 2 V -1 s -1

Q. A potential difference of $5 V$ is applied across a conductor of length $10 c m$ . If drift velocity of electrons is $2.5 \times 1 0^{- 4} m / s$ , then electron mobility will be

$5 \times 1 0^{- 4} m^{2} V^{- 1} s^{- 1}$

$5 \times 1 0^{- 6} m^{2} V^{- 1} s^{- 1}$

$5 \times 1 0^{- 2} m^{2} V^{- 1} s^{- 1}$

Zero

$μ = \frac{V _{D}}{E}$
$μ = \frac{2.5 \times 1 0 ^{- 4} \times 0.1}{5}$
$μ = 5 \times 1 0^{- 6} m^{2} V^{- 1} s^{- 1}$

Q. A potential difference of 5V is applied across a conductor of length 10cm. If drift velocity of electrons is 2.5×10−4m/s, then electron mobility will be

5×10−4m2V−1s−1

5×10−6m2V−1s−1

5×10−2m2V−1s−1