A potential difference of 20 kV is applied across an X- ray tube. The minimum wavelength of X- rays generated (in angstrom) is

Question

A potential difference of 20 kV is applied across an X- ray tube. The minimum wavelength of X- rays generated (in angstrom) is (A) 0.62 (B) 1.24 (C) 0.31 (D) 6.2

Tardigrade Admin · Accepted Answer

For X -rays production (hc/λmin)=eV λmin=(hc/eV) =(6.63×10-34×3×108/1.6×10-19×20×103) =0.62×10-10 m =0.62 mathringA

Q. A potential difference of $20 kV$ is applied across an $X$ - ray tube. The minimum wavelength of $X$ - rays generated (in angstrom) is

$0.62$

$1.24$

$0.31$

$6.2$

For $X$ -rays production
$\frac{h c}{λ _{min}} = e V$
$λ_{min} = \frac{h c}{e V}$
$= \frac{6.63 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{1.6 \times 1 0 ^{- 19} \times 20 \times 1 0 ^{3}}$
$= 0.62 \times 1 0^{- 10} m$
$= 0.62 \overset{˚}{A}$

Q. A potential difference of 20kV is applied across an X- ray tube. The minimum wavelength of X- rays generated (in angstrom) is

0.62

1.24

0.31

6.2