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Physics
A potential difference of 20 kV is applied across an X- ray tube. The minimum wavelength of X- rays generated (in angstrom) is
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Q. A potential difference of $20 \,kV$ is applied across an $X$- ray tube. The minimum wavelength of $X$- rays generated (in angstrom) is
UP CPMT
UP CPMT 2010
Atoms
A
$0.62$
75%
B
$1.24$
0%
C
$0.31$
25%
D
$6.2$
0%
Solution:
For $X$ -rays production
$\frac{hc}{\lambda_{min}}=eV $
$\lambda_{min}=\frac{hc}{eV}$
$=\frac{6.63\times10^{-34}\times3\times10^{8}}{1.6\times10^{-19}\times20\times10^{3}}$
$=0.62\times10^{-10}\,m$
$=0.62\, \mathring{A}$