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Q. A potential difference of $20 \,kV$ is applied across an $X$- ray tube. The minimum wavelength of $X$- rays generated (in angstrom) is

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Solution:

For $X$ -rays production
$\frac{hc}{\lambda_{min}}=eV $
$\lambda_{min}=\frac{hc}{eV}$
$=\frac{6.63\times10^{-34}\times3\times10^{8}}{1.6\times10^{-19}\times20\times10^{3}}$
$=0.62\times10^{-10}\,m$
$=0.62\, \mathring{A}$