A positively charged ball hangs from a long silk thread. Electric field at a certain point (at the same horizontal level of ball) due to this charge is E. Let us put a positive test charge q0 at this point and measure F / q0 on this charge. Then, E

Question

A positively charged ball hangs from a long silk thread. Electric field at a certain point (at the same horizontal level of ball) due to this charge is E. Let us put a positive test charge q0 at this point and measure F / q0 on this charge. Then, E (A) >F / q0 (B) < F / q0 (C) =F / q0 (D) none of these

Tardigrade Admin · Accepted Answer

E=(k Q/r2) .....(i) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/8b39af039c8190f34223a3c4825b98c5-.png" /> F=(k Q q0/r12) or (F/q0)=(k Q/r12)....(ii) As r1>r, so from Eqs. (i) and (ii), we get E>F / q0

Q. A positively charged ball hangs from a long silk thread. Electric field at a certain point (at the same horizontal level of ball) due to this charge is $E$ . Let us put a positive test charge $q_{0}$ at this point and measure $F / q_{0}$ on this charge. Then, $E$

$> F / q_{0}$

$< F / q_{0}$

$= F / q_{0}$

none of these

$E = \frac{k Q}{r ^{2}}$ .....(i)

$F = \frac{k Q q _{0}}{r _{1}^{2}}$
or $\frac{F}{q _{0}} = \frac{k Q}{r _{1}^{2}}$ ....(ii)
As $r_{1} > r$ , so from Eqs. (i) and (ii),
we get $E > F / q_{0}$

Q. A positively charged ball hangs from a long silk thread. Electric field at a certain point (at the same horizontal level of ball) due to this charge is E. Let us put a positive test charge q0​ at this point and measure F/q0​ on this charge. Then, E

>F/q0​

<F/q0​

=F/q0​