A positive point charge is placed at P in front of an earthed metal sheet S . Q and R are two points between P and S as shown in the figure. If the electric field strength at Q and R are respectively EQ , ER and potential at Q and R are respectively VQ , VR . Then

Question

A positive point charge is placed at P in front of an earthed metal sheet S . Q and R are two points between P and S as shown in the figure. If the electric field strength at Q and R are respectively EQ , ER and potential at Q and R are respectively VQ , VR . Then Question

(A) EQ=ER (B) EQ < ER (C) VQ>VR (D) VQ < VR

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-jfymcs985xqxcmp0.jpg" /> As we move away from P towards sheet S spacing between electric lines of force is increasing. ∴ ER < EQ In direction of electric field potential decreases. ∴ VR < VQ

$E_{Q} = E_{R}$

$E_{Q} < E_{R}$

$V_{Q} > V_{R}$

$V_{Q} < V_{R}$

As we move away from $P$ towards sheet $S$ spacing between electric lines of force is increasing. $∴ E_{R} < E_{Q}$
In direction of electric field potential decreases. $∴ V_{R} < V_{Q}$

Q. A positive point charge is placed at P in front of an earthed metal sheet S . Q and R are two points between P and S as shown in the figure. If the electric field strength at Q and R are respectively EQ​ , ER​ and potential at Q and R are respectively VQ​ , VR​ . Then

EQ​=ER​

EQ​<ER​

VQ​>VR​

VQ​<VR​

As we move away from P towards sheet S spacing between electric lines of force is increasing. ∴ER​<EQ​ In direction of electric field potential decreases. ∴VR​<VQ​

$E_{Q} = E_{R}$

$E_{Q} < E_{R}$

$V_{Q} > V_{R}$

$V_{Q} < V_{R}$

As we move away from $P$ towards sheet $S$ spacing between electric lines of force is increasing. $∴ E_{R} < E_{Q}$
In direction of electric field potential decreases. $∴ V_{R} < V_{Q}$