A pop- gun consists of a cylindrical barrel 3cm2 in cross- section closed at one end by a cork and having a well fitting piston at the other. If the piston is pushed slowly in , the cork is finally ejected, giving a pop, the frequency of which is found to be 512 Hz. Assuming that the initial distance between the cork and the piston was 25 cm and that there is no leakage of air, calculate the force required to eject the cork. Atmospheric pressure= 1 kg/cm2, v=340 m/s

Question

A pop- gun consists of a cylindrical barrel 3cm2 in cross- section closed at one end by a cork and having a well fitting piston at the other. If the piston is pushed slowly in , the cork is finally ejected, giving a pop, the frequency of which is found to be 512 Hz. Assuming that the initial distance between the cork and the piston was 25 cm and that there is no leakage of air, calculate the force required to eject the cork. Atmospheric pressure= 1 kg/cm2, v=340 m/s (A) 1.5 kg .wt (B) 3 kg .wt (C) 6 kg .wt (D) 8 kg .wt

Tardigrade Admin · Accepted Answer

n = (V/4L) , Boyles law. PV = P1 V1 F = Δ p × A

1.5 kg .wt

3 kg .wt

6 kg .wt

8 kg .wt

n=4LV​ , Boyles law. PV=P1V1 F=Δp×A

$n = \frac{V}{4 L}$ , Boyles law. $P V = P^{1} V^{1}$
$F = Δ p \times A$