A polyatomic gas with n degrees of freedom has a mean energy per molecule given by

Question

A polyatomic gas with n degrees of freedom has a mean energy per molecule given by (A)  (nkT/N) (B)  (nkT/2N)  (C)  (nkT/2)  (D)  (3kT/2)

Tardigrade Admin · Accepted Answer

According to law of equipartition of energy, the energy per degree of freedom is (1/2)kT. For a polyatomic gas with n degrees of freedom, the mean energy per molcule = (1/2)nkT

Q. A polyatomic gas with n degrees of freedom has a mean energy per molecule given by

$\frac{nk T}{N}$

$\frac{nk T}{2 N}$

$\frac{nk T}{2}$

$\frac{3 k T}{2}$

According to law of equipartition of energy,
the energy per degree of freedom is $\frac{1}{2} k T .$ For a
polyatomic gas with n degrees of freedom, the
mean energy per molcule $= \frac{1}{2} nk T$

Q. A polyatomic gas with n degrees of freedom has a mean energy per molecule given by

NnkT​

2NnkT​

2nkT​

23kT​

According to law of equipartition of energy, the energy per degree of freedom is 21​kT. For a polyatomic gas with n degrees of freedom, the mean energy per molcule =21​nkT

$\frac{nk T}{N}$

$\frac{nk T}{2 N}$

$\frac{nk T}{2}$

$\frac{3 k T}{2}$

According to law of equipartition of energy,
the energy per degree of freedom is $\frac{1}{2} k T .$ For a
polyatomic gas with n degrees of freedom, the
mean energy per molcule $= \frac{1}{2} nk T$