A point Q lies on the perpendicular bisector of an electrical dipole of dipole moment p. If the distance of Q from the dipole is r (much larger than the size of the dipole), then the electric field at Q is proportional to

Question

A point Q lies on the perpendicular bisector of an electrical dipole of dipole moment p. If the distance of Q from the dipole is r (much larger than the size of the dipole), then the electric field at Q is proportional to (A)  p2 and r - 3  (B) p and r - 2 (C)  p - 1 and r - 2 (D) p and r-3

Tardigrade Admin · Accepted Answer

he electric field at a point on equatorial line (perpendicular bisector) of dipole at a distance r is given by, E =

\frac{P}{4 π ε _{0}} \cdot \frac{1}{( r ^{2} + a ^{2} ) ^{3/2}}

where 2 a = length of dipole

(∵

r > > a)

∴ E = \frac{P}{4 π ε _{0}} \cdot \frac{1}{r ^{3}} \cdot

i, e., E

\propto

p and E

\propto r^{- 3}

.

Q. A point Q lies on the perpendicular bisector of an electrical dipole of dipole moment p. If the distance of Q from the dipole is r (much larger than the size of the dipole), then the electric field at Q is proportional to

$p^{2}$ and $r^{- 3}$

p and $r^{- 2}$

$p^{- 1}$ and $r^{- 2}$

p and $r^{- 3}$

Q. A point Q lies on the perpendicular bisector of an electrical dipole of dipole moment p. If the distance of Q from the dipole is r (much larger than the size of the dipole), then the electric field at Q is proportional to

p2 and r−3

p and r−2

p−1 and r−2

p and r−3

he electric field at a point on equatorial line (perpendicular bisector) of dipole at a distance r is given by, E = 4πε0​P​⋅(r2+a2)3/21​ where 2 a = length of dipole (∵ r > > a) ∴E=4πε0​P​⋅r31​⋅ i, e., E ∝ p and E ∝r−3.

$p^{2}$ and $r^{- 3}$

p and $r^{- 2}$

$p^{- 1}$ and $r^{- 2}$

p and $r^{- 3}$