A point on the periphery of rotating disc has its acceleration vector making on angle 30o with velocity vector, then the ratio of magnitude of centripetal acceleration to tangential acceleration is

Question

A point on the periphery of rotating disc has its acceleration vector making on angle 30o with velocity vector, then the ratio of magnitude of centripetal acceleration to tangential acceleration is (A) sin 30o (B) cos 30o (C) tan 30o (D) none of these

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/0a10fd085835c7ec424dbffde25efaf8-.png" /> From the diagram, (aN/at)=tan θ =tan â¡ 30o

Q. A point on the periphery of rotating disc has its acceleration vector making on angle $3 0^{o}$ with velocity vector, then the ratio of magnitude of centripetal acceleration to tangential acceleration is

$s in 3 0^{o}$

$cos 3 0^{o}$

$t an 3 0^{o}$

none of these

From the diagram, $\frac{a _{N}}{a _{t}} = t an θ = t an 3 0^{o}$

Q. A point on the periphery of rotating disc has its acceleration vector making on angle 30o with velocity vector, then the ratio of magnitude of centripetal acceleration to tangential acceleration is

sin30o

cos30o

tan30o