A point object is placed at the centre of a glass sphere of radius 6 cm and refractive index 1.5 . The distance of the virtual image from the surface of the sphere is

Question

A point object is placed at the centre of a glass sphere of radius 6 cm and refractive index 1.5 . The distance of the virtual image from the surface of the sphere is (A) 2 cm (B) 4 cm (C) 6 cm (D) 12 cm

Tardigrade Admin · Accepted Answer

(μ2/v)-(μ1/u)=(μ2-μ1/R) μ2=1.5, μ1=1, u=-6 cm , R=-6 cm (1.5/v)-(1/(-6))=(1.5-1/(-6)) ⇒ v=-6 cm

Q. A point object is placed at the centre of a glass sphere of radius $6 c m$ and refractive index $1.5.$ The distance of the virtual image from the surface of the sphere is

2 cm

4 cm

6 cm

12 cm

$\frac{μ _{2}}{v} - \frac{μ _{1}}{u} = \frac{μ _{2} - μ _{1}}{R}$
$μ_{2} = 1.5, μ_{1} = 1, u = - 6 c m, R = - 6 c m$
$\frac{1.5}{v} - \frac{1}{( - 6 )} = \frac{1.5 - 1}{( - 6 )} \Rightarrow v = - 6 c m$

Q. A point object is placed at the centre of a glass sphere of radius 6cm and refractive index 1.5. The distance of the virtual image from the surface of the sphere is