Question

A point object is kept just beyond the first focus of a convex lens. If the lens starts moving towards the right with a constant velocity, the image will

• A. always move towards right
• B. always move towards left
• C. first move towards right and then towards left
• D. first move towards left and then towards right

Answer 1

Answer: (D)

$\frac{\text{dv}}{\text{dt}}={\left(\frac{\text{v}}{\text{u}}\right)}^2\times \frac{\text{du}}{\text{dt}}$
${\mathrm{V}}_{\text{image/lens }}={\left(\frac{\mathrm{V}}{\mathrm{u}}\right)}^2\times {\mathrm{V}}_{\text{object/lens }}$
till $u$ become $2f$ , $m>-1$ so $V_{image/lens}>V_{object/lens}$ and the image will move towards left and when
$u$ become $>2f$ , $V_{image/lens}<V_{object/lens}$ and the image will move towards the right.