A point charge of 50 μ C is placed in the X Y -plane at a location with radius vector r 0=2 hat i +3 hat j m . The electric field strength and its magnitude at a point with radius vector r =8 hat i -5 hat j m is (ε0=8.85 × 10-12 C 2 / N - m 2)

Question

A point charge of 50 μ C is placed in the X Y -plane at a location with radius vector r 0=2 hat i +3 hat j m . The electric field strength and its magnitude at a point with radius vector r =8 hat i -5 hat j m is (ε0=8.85 × 10-12 C 2 / N - m 2) (A) 4.5 kV / m (B) 45 kV / m (C) 0.45 kV / m (D) 450 kV / m

Tardigrade Admin · Accepted Answer

Distance between point charge and observation point is x = r - r 0=6 hat i -8 hat j Magnitude of x =x=√62+82 x=10 m ∴ Electric field, E=(K q/x2) =(9 × 109 × 50 × 10-6/10 × 10) =4.5 kV m

Q. A point charge of $50 μ C$ is placed in the $X Y$ -plane at a location with radius vector $r_{0} = 2 \hat{i} + 3 \hat{j} m .$ The electric field strength and its magnitude at a point with radius vector $r = 8 \hat{i} - 5 \hat{j} m$ is
$(ε_{0} = 8.85 \times 1 0^{- 12} C^{2} / N - m^{2})$

4.5 kV / m

45 kV / m

0.45 kV / m

450 kV / m

Distance between point charge and observation point is
$x = r - r_{0} = 6 \hat{i} - 8 \hat{j}$
Magnitude of $x = x = 6^{2} + 8^{2}$
$x = 10 m$
$∴$ Electric field, $E = \frac{K q}{x ^{2}}$
$= \frac{9 \times 1 0 ^{9} \times 50 \times 1 0 ^{- 6}}{10 \times 10}$
$= 4.5 kV m$

Q. A point charge of 50μC is placed in the XY -plane at a location with radius vector r0​=2i^+3j^​m. The electric field strength and its magnitude at a point with radius vector r=8i^−5j^​m is (ε0​=8.85×10−12C2/N−m2)