A point charge of 10 μ C is placed at the origin. At what location on the X-axis should a point charge of 40 μ C be placed so that the net electric field is zero at x=2 cm on the X-axis?

Question

A point charge of 10 μ C is placed at the origin. At what location on the X-axis should a point charge of 40 μ C be placed so that the net electric field is zero at x=2 cm on the X-axis? (A) x=-4 cm (B) x=4 cm (C) x=8 cm (D) x=6 cm

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/306449d609998d2254f9fc77e6e9407a-.png" /> EP=(K × 10/22)-(K × 40/(x0-2)2)=0 (1/2)=(2/x0-2) x0-2=4 x0=6 cm

Q. A point charge of $10 μ C$ is placed at the origin. At what location on the $X$ -axis should a point charge of $40 μ C$ be placed so that the net electric field is zero at $x = 2 c m$ on the $X$ -axis?

$x = - 4 c m$

$x = 4 c m$

$x = 8 c m$

$x = 6 c m$

$E_{P} = \frac{K \times 10}{2 ^{2}} - \frac{K \times 40}{( x _{0} - 2 ) ^{2}} = 0$
$\frac{1}{2} = \frac{2}{x _{0} - 2}$
$x_{0} - 2 = 4$
$x_{0} = 6 c m$

Q. A point charge of 10μC is placed at the origin. At what location on the X-axis should a point charge of 40μC be placed so that the net electric field is zero at x=2cm on the X-axis?

x=−4cm

x=4cm

x=8cm

x=6cm