A player kicks a football with an initial speed of 25 ms -1 at an angle of 45° from the ground. What are the maximum height and the time taken by the football to reach at the highest point during motion ? (Take g =10 ms -2 )

Question

A player kicks a football with an initial speed of 25 ms -1 at an angle of 45° from the ground. What are the maximum height and the time taken by the football to reach at the highest point during motion ? (Take g =10 ms -2 ) (A) h max =10 m T =2.5 s (B) h max =15.625 m T =3.54 s (C) h max =15.625 m T =1.77 s (D) h max =3.54 m T =0.125 s

Tardigrade Admin · Accepted Answer

H =( U 2 sin 2 θ/2 g ) =((25)2 ⋅( sin 45)2/2 × 10) =15.625 m T =( U sin θ/ g ) =(25 × sin 45°/10) =2.5 × 0.7 =1.77 s

Q. A player kicks a football with an initial speed of $25 m s^{- 1}$ at an angle of $4 5^{\circ}$ from the ground. What are the maximum height and the time taken by the football to reach at the highest point during motion ? (Take $g = 10 m s^{- 2}$ )

$h_{m a x} = 10 m T = 2.5 s$

$h_{m a x} = 15.625 m T = 3.54 s$

$h_{m a x} = 15.625 m T = 1.77 s$

$h_{m a x} = 3.54 m T = 0.125 s$

$H = \frac{U ^{2} s i n ^{2} θ}{2 g}$
$= \frac{( 25 ) ^{2} \cdot ( s i n 45 ) ^{2}}{2 \times 10}$
$= 15.625 m$
$T = \frac{U s i n θ}{g}$
$= \frac{25 \times s i n 4 5 ^{\circ}}{10}$
$= 2.5 \times 0.7$
$= 1.77 s$

Q. A player kicks a football with an initial speed of 25ms−1 at an angle of 45∘ from the ground. What are the maximum height and the time taken by the football to reach at the highest point during motion ? (Take g=10ms−2 )

hmax​=10mT=2.5s

hmax​=15.625mT=3.54s

hmax​=15.625mT=1.77s

hmax​=3.54mT=0.125s