A planet revolves in an elliptical orbit around the sun. The semi-major and semi-minor axes are a and b. Then the square of time period, T is directly proportional to

Question

A planet revolves in an elliptical orbit around the sun. The semi-major and semi-minor axes are a and b. Then the square of time period, T is directly proportional to (A) a3 (B) b3 (C) ((a+b/2))3 (D) ((a-b/2))3

Tardigrade Admin · Accepted Answer

The square of the period of planet is directly proportional to the cube of the semi-major axis of the elliptical orbit. ⇒ T2 propto a3

Q. A planet revolves in an elliptical orbit around the sun. The semi-major and semi-minor axes are $a$ and $b$ . Then the square of time period, $T$ is directly proportional to

$a^{3}$

$b^{3}$

$(\frac{a + b}{2})^{3}$

$(\frac{a - b}{2})^{3}$

The square of the period of planet is directly proportional to the cube of the semi-major axis of the elliptical orbit.
$\Rightarrow T^{2} \propto a^{3}$

Q. A planet revolves in an elliptical orbit around the sun. The semi-major and semi-minor axes are a and b. Then the square of time period, T is directly proportional to

a3

b3

(2a+b​)3

(2a−b​)3