A plane progressive wave is given by y= 2 cos 6.284(330 t - x). What is period of the wave?

Question

A plane progressive wave is given by y= 2 cos 6.284(330 t - x). What is period of the wave? (A) (1/330)s (B) 2 π × 330 s (C) (2 π × 330)-1 s (D) (6.284/330) s

Tardigrade Admin · Accepted Answer

We have the progressive wave given by y = 2 cos 6.284 (330 t - x) = 2 cos 2 π (330 t - x) = 2 cos (2 π × 330 t - 2 π x) ω = 2 π × 330, and time period T = (2 π/ω) = (1/330) s.

Q. A plane progressive wave is given by y= 2 cos 6.284(330 t - x). What is period of the wave?

$\frac{1}{330} s$

$2 π \times 330 s$

$(2 π \times 330)^{- 1} s$

$\frac{6.284}{330} s$

We have the progressive wave given by
$y = 2 cos 6.284 (330 t - x)$
$= 2 cos 2 π (330 t - x)$
$= 2 cos (2 π \times 330 t - 2 π x)$
$ω = 2 π \times 330,$
and time period T = $\frac{2 π}{ω} = \frac{1}{330} s .$

Q. A plane progressive wave is given by y= 2 cos 6.284(330 t - x). What is period of the wave?

3301​s

2π×330s

(2π×330)−1s

3306.284​s

We have the progressive wave given by y=2cos6.284(330t−x) =2cos2π(330t−x) =2cos(2π×330t−2πx) ω=2π×330, and time period T = ω2π​=3301​s.

$\frac{1}{330} s$

$2 π \times 330 s$

$(2 π \times 330)^{- 1} s$

$\frac{6.284}{330} s$

We have the progressive wave given by
$y = 2 cos 6.284 (330 t - x)$
$= 2 cos 2 π (330 t - x)$
$= 2 cos (2 π \times 330 t - 2 π x)$
$ω = 2 π \times 330,$
and time period T = $\frac{2 π}{ω} = \frac{1}{330} s .$