A plane electromagnetic wave of frequency 25 GHz is propagating in vacuum along the z-direction. At a particular point in space and time, the magnetic field is given by vecB=5×10-8 hatj T. The corresponding electric field vecE is (speed of light c = 3 × 108 ms-1)

Question

A plane electromagnetic wave of frequency 25 GHz is propagating in vacuum along the z-direction. At a particular point in space and time, the magnetic field is given by vecB=5×10-8 hatj T. The corresponding electric field vecE is (speed of light c = 3 × 108 ms-1) (A) -1.66 × 10-16 hati V /m (B) 1.66 × 10-16 hati V /m (C) -15 hati V /m (D) 15 hati V /m

Tardigrade Admin · Accepted Answer

E= vecB× vecV =(5×10-8 hatj)×(3×108 hatk) =15 hati V / m

Q. A plane electromagnetic wave of frequency 25 GHz is propagating in vacuum along the z-direction. At a particular point in space and time, the magnetic field is given by $B = 5 \times 1 0^{- 8} \hat{j} T$ . The corresponding electric field $E$ is (speed of light $c = 3 \times 1 0^{8} m s^{- 1}$ )

$- 1.66 \times 1 0^{- 16} \hat{i} V / m$

$1.66 \times 1 0^{- 16} \hat{i} V / m$

$- 15 \hat{i} V / m$

$15 \hat{i} V / m$

$E = B \times V$
$= (5 \times 1 0^{- 8} \hat{j}) \times (3 \times 1 0^{8} \hat{k})$
$= 15 \hat{i} V / m$

Q. A plane electromagnetic wave of frequency 25 GHz is propagating in vacuum along the z-direction. At a particular point in space and time, the magnetic field is given by B=5×10−8j^​T. The corresponding electric field E is (speed of light c=3×108ms−1)

−1.66×10−16i^V/m

1.66×10−16i^V/m

−15i^V/m

15i^V/m