A plane containing the point (3, 2, 0) and the line (x-1/1)=(y-2/5)=(z-3/4) also contains the point :

Question

A plane containing the point (3, 2, 0) and the line (x-1/1)=(y-2/5)=(z-3/4) also contains the point : (A) (0, -3, 1) (B) (0, 7, 10) (C) (0, 7, -10) (D) (0, 3, 1)

Tardigrade Admin · Accepted Answer

Equation of plane containing the point A(3,2,0) and the line |x-1 y-2 z-3 3-1 2-2 0-3 1 5 4|=0 i.e., (x-1)(15)-(y-2)(11)+(z-3)(10) =0 i.e. 15 x-11 y+10 z-23=0 clearly (0,7,10) satisfy it, as 15(0)-11(7)+10(10)-23 =-77+100-23=0

Q. A plane containing the point $(3, 2, 0)$ and the line $\frac{x - 1}{1} = \frac{y - 2}{5} = \frac{z - 3}{4}$ also contains the point :

$(0, - 3, 1)$

$(0, 7, 10)$

$(0, 7, - 10)$

$(0, 3, 1)$

Q. A plane containing the point (3,2,0) and the line 1x−1​=5y−2​=4z−3​ also contains the point :

(0,−3,1)

(0,7,10)

(0,7,−10)

(0,3,1)

Equation of plane containing the point A(3,2,0) and the line ∣∣​x−13−11​y−22−25​z−30−34​∣∣​=0 i.e., (x−1)(15)−(y−2)(11)+(z−3)(10)=0 i.e. 15x−11y+10z−23=0 clearly (0,7,10) satisfy it, as 15(0)−11(7)+10(10)−23=−77+100−23=0

Q. A plane containing the point $(3, 2, 0)$ and the line $\frac{x - 1}{1} = \frac{y - 2}{5} = \frac{z - 3}{4}$ also contains the point :

$(0, - 3, 1)$

$(0, 7, 10)$

$(0, 7, - 10)$

$(0, 3, 1)$