A pipe open at both the ends produces a note of fundamental frequency f1 . When the pipe is kept with (3/4) th of its length in water, it produces a note of fundamental frequency f2 . The ratio of (f1/f2) is:

Question

A pipe open at both the ends produces a note of fundamental frequency f1 . When the pipe is kept with (3/4) th of its length in water, it produces a note of fundamental frequency f2 . The ratio of (f1/f2) is: (A)  (4/3)  (B)  (3/4)  (C)  2  (D)  (1/2)

Tardigrade Admin · Accepted Answer

Accordingly, f1=(v/2l) .. (1) and f2=(v/4l/4)=(v/l) .. (2) Hence, (f1/f2)=(1/2)

Q. A pipe open at both the ends produces a note of fundamental frequency $f_{1}$ . When the pipe is kept with $\frac{3}{4}$ th of its length in water, it produces a note of fundamental frequency $f_{2}$ . The ratio of $\frac{f _{1}}{f _{2}}$ is:

$\frac{4}{3}$

$\frac{3}{4}$

$2$

$\frac{1}{2}$

$\frac{3}{2}$

Accordingly, $f_{1} = \frac{v}{2 l}$ .. (1)
and $f_{2} = \frac{v}{4 l /4} = \frac{v}{l}$ .. (2)
Hence, $\frac{f _{1}}{f _{2}} = \frac{1}{2}$

Q. A pipe open at both the ends produces a note of fundamental frequency f1​ . When the pipe is kept with 43​ th of its length in water, it produces a note of fundamental frequency f2​ . The ratio of f2​f1​​ is:

34​

43​

2

21​

23​

Accordingly, f1​=2lv​ .. (1) and f2​=4l/4v​=lv​ .. (2) Hence, f2​f1​​=21​