A piece of wire is cut into four equal parts and the pieces are bundled together side by side to form a thicker wire. Compared with that of the original wire, the resistance of the bundle is

Question

A piece of wire is cut into four equal parts and the pieces are bundled together side by side to form a thicker wire. Compared with that of the original wire, the resistance of the bundle is (A) The same (B) (1/16) as much (C) (1/8) as much (D) (1/4) as much

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/4a921c5c9a9276885205964916301648-.png" /> R textnet=(R/16)

Q. A piece of wire is cut into four equal parts and the pieces are bundled together side by side to form a thicker wire. Compared with that of the original wire, the resistance of the bundle is

The same

$\frac{1}{16}$ as much

$\frac{1}{8}$ as much

$\frac{1}{4}$ as much

$R_{net} = \frac{R}{16}$

Q. A piece of wire is cut into four equal parts and the pieces are bundled together side by side to form a thicker wire. Compared with that of the original wire, the resistance of the bundle is

The same

161​ as much

81​ as much

41​ as much

Rnet​=16R​

$\frac{1}{16}$ as much

$\frac{1}{8}$ as much

$\frac{1}{4}$ as much

$R_{net} = \frac{R}{16}$