A piece of solid weighs 120 g in air, 80 g in water and 60 kg in a liquid. The relative density of the solid and that of the liquid are respectively

Question

A piece of solid weighs 120 g in air, 80 g in water and 60 kg in a liquid. The relative density of the solid and that of the liquid are respectively (A) 2, (1/2) (B) 2, (3/2) (C) 3, (1/2) (D) 3, (3/2)

Tardigrade Admin · Accepted Answer

Relative density of solid =( textweight in air / textweight in air â weight in water ) =(120/120-80)=(120/40)=3 Relative density of liquid =( textweight in air - weight in liquid / textweight in air - weight in water) =(120-60/120-80)=(60/40)=(3/2)

Q. A piece of solid weighs $120 g$ in air, $80 g$ in water and $60 k g$ in a liquid. The relative density of the solid and that of the liquid are respectively

$2, \frac{1}{2}$

$2, \frac{3}{2}$

$3, \frac{1}{2}$

$3, \frac{3}{2}$

Relative density of solid
$= \frac{weight in air}{weight in air — weight in water}$
$= \frac{120}{120 - 80} = \frac{120}{40} = 3$
Relative density of liquid
$= \frac{weight in air - weight in liquid}{weight in air - weight in water}$
$= \frac{120 - 60}{120 - 80} = \frac{60}{40} = \frac{3}{2}$

Q. A piece of solid weighs 120g in air, 80g in water and 60kg in a liquid. The relative density of the solid and that of the liquid are respectively

2,21​

2,23​

3,21​

3,23​