Question

A person with his hand in his pocket is skating on ice at the rate of $10m/s$ and describes a circle of radius $50m$. What is his inclination to vertical : $(g=10m/se{c}^2)$

• A. $ta{n}^{-1}\left(1/2\right)$
• B. $ta{n}^{-1}\left(1/5\right)$
• C. $ta{n}^{-1}\left(3/5\right)$
• D. $ta{n}^{-1}\left(1/10\right)$

Answer 1

Answer: (B)

The inclination of person from vertical is given by,
$\tan \theta =\frac{v^2}{rg}=\frac{(10{)}^2}{50\times 10}=\frac{1}{5}$
$\therefore \theta ={\tan }^{-1}(1/5)$