Question

A person with his hand in his pocket is skating on ice at the rate of $10\,m/s$ and describes a circle of radius $50 \,m$. What is his inclination to vertical : $(g = 10\,m/ sec ^2)$

• A. $tan^{-1}\left(1/2\right)$
• B. $tan^{-1}\left(1/5\right)$
• C. $tan^{-1}\left(3/5\right)$
• D. $tan^{-1}\left(1/10\right)$

Answer 1

Answer: (B)

The inclination of person from vertical is given by,
$\tan \theta=\frac{ v ^{2}}{ rg }=\frac{(10)^{2}}{50 \times 10}=\frac{1}{5} $
$\therefore \theta=\tan ^{-1}(1 / 5)$