A person standing on the floor of an elevator drops a coin. The coin reaches the floor in time t1 if the elevator is at rest and in time t2 if the elevator is moving uniformly. Then :-

Question

A person standing on the floor of an elevator drops a coin. The coin reaches the floor in time t1 if the elevator is at rest and in time t2 if the elevator is moving uniformly. Then :- (A) t1 < t2 or t1 > t2 depending upon whether the lift is going up or down (B) t1 < t2 (C) t1 > t2 (D) t1 = t2

Tardigrade Admin · Accepted Answer

t = √(2h/arel) In both cases arel = g - 0 = g. Hence t1 = t2

Q. A person standing on the floor of an elevator drops a coin. The coin reaches the floor in time t₁ if the elevator is at rest and in time t₂ if the elevator is moving uniformly. Then :-

t₁ < t₂ or t₁ > t₂ depending upon whether the lift is going up or down

t₁ < t₂

t₁ > t₂

t₁ = t₂

$t = \frac{2 h}{a _{re l}}$
In both cases $a_{re l} = g - 0 = g$ .
Hence $t_{1} = t_{2}$

Q. A person standing on the floor of an elevator drops a coin. The coin reaches the floor in time t1 if the elevator is at rest and in time t2 if the elevator is moving uniformly. Then :-

t1 < t2 or t1 > t2 depending upon whether the lift is going up or down

t1 < t2

t1 > t2

t1 = t2